I just tripped across this on youtube: . He calculates a typical savings of gas, for a typical car in a stop from 100 km/hr to 0. I translated it to the Clarity where some of his "typical" numbers are known, and to imperial units. I included the formulas I used in Excel; most was just cut-and-pasted, so excuse any bad formatting: Curb Mass 4052 lb =1838.0 kg Total mass m = 4409.2 lb = 2000 kg (Assumed) Speed v = 60 mph = 26.8224 m/sec. Kinetic Energy K.E. = 719.4 KJoule = m*v^2/2000 Regen. Brake Efficiency 60% (Assumed; his number) Energy Recovered 431.7 KJoule =K.E.*R.B.Eff. Therm. Eff. 41% (If I recall correctly) Gas Saved 0.024485 kg =Recov./43000/Th.Eff. Gas Saved 0.008624 gal (@ 0.75 kg/l) Gas Saved 1.1039 oz. Stops/Gal = 115.9525 I don't know if the regenerative braking efficiency should be different.
